Create A Menu Using Pure Css And Html
Solution 1:
HTML
<ulclass="menu"><li>
item1
<ul><li><ahref="#">subitem1</a></li><li><ahref="#">subitem2</a></li><li><ahref="#">subitem3</a></li><li><ahref="#">subitem4</a></li><li>
item2
<ul><li><ahref="#">subitem5</a></li><li><ahref="#">subitem6</a></li><li><ahref="#">subitem7</a></li><li><ahref="#">subitem8</a></li></ul></li></ul></li></ul>
CSS
.menuli > ul {
display:none;
}
.menuli:hover > ul {
display:block;
}
Solution 2:
Something like this? (Without changing your html)
CSS:
ulliul {display:none;}
ul > li:hoverul{display:block;}
ulliul > li > ul.sub-ul-2 {display:none;}
ul > li:hoverul > li:hoverul{display:block;}
Update: (Without using any classes & cursos:pointer;)
ulliul {display:none;}
ul > li:hoverul{display:block;}
ul > li > ul > li > ul > li{display:none;}
ul > li:hoverul > li:hoverulli{display:block;}
li{cursor:pointer;} /* For the hand (cursor) while hover over the li */
Or the short css, after fixing the first ul from <ul class"menu">
to <ul class="menu">
(By adding the = to it)
.menuul {display:none;}
.menuli:hover > ul{display:block;}
li{cursor:pointer;}
Solution 3:
fiddle: http://jsfiddle.net/Z22kH/
html:
<ulclass="menu"><li><a>item1</a><ulclass="sub-ul-1"><li><a>subitem1</a></li><li><a>subitem2</a></li><li><a>subitem3</a></li><li><a>subitem4</a></li><li><a>item2</a><ulclass="sub-ul-2"><li><a>subitem5</a></li><li><a>subitem6</a></li><li><a>subitem7</a></li><li><a>subitem8</a></li></ul></li></ul></li></ul>
css:
ul.menuli{
display: none;
}
ul.menu > li{
display: block;
}
ul.menu > li:hover > ul > li,
ul.menuul > li:hover > ul > li{
display:block;
}
Solution 4:
I've put together a working and minimalistic jsfiddle demo.
You hide all UL's inside .menu
. Upon hovering any list-item, you reveal any direct descendant UL. I use display: block;
and display: none;
for the purpose of keeping it simple.
CSS:
/* Hide all UL's inside .menu */.menuul {
display: none;
}
/* Show any UL which is a direct child of a hovered list-item */.menuli:hover > ul {
display: block;
}
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