Multiple Java Script In One Page Error June 21, 2023 Post a Comment I have this code that is working originally: Please SelectSolution 1: As suggested in Comments, you made mistakes in your code;1.Binding change function with wrong selector id $("#Name2").change(function(){ Copyand the HTML is<select name="Name" required class="form-control" id="Name"> CopyShould be $("#Name").change(function(){ it will fix the problem Undefined selname at line 52.Name Ajax Method success functionsuccess: function(data) { $("#Schedule2").html(dataname); } CopyShould be $("#Schedule2").html(data);And in PHP; credit goes to @j08691change $selDate$selDate = $_POST['selname']; Copyto $selname$selname = $_POST['selname']; $sql="SELECT * FROM clinic.appoint WHERE name='$selname'"; CopyAs you said in question, your first Ajax Call is working fine and you are facing problem in 2nd Ajax call method, after fixing above mistakesHTML<th><selectname="Name"requiredclass="form-control"id="Name"><optionvalue="">Please Select Name</option><?php$sql3="SELECT * FROM clinic.appoint GROUP BY name"; $result3 = mysqli_query($con, $sql3) ordie($sql3."<br/><br/>".mysql_error()); while($rows3=mysqli_fetch_array($result3)){?><optionvalue="<?phpecho$rows3['name'] ?>"><?phpecho$rows3['name'] ?></option><?php } ?></select></th>CopyAJAX$(document).ready(function(){ $("#Name").change(function(){ var selname =$(this).val(); display_name(selname); }); // This is the function...functiondisplay_name(selname) { $("#scheduleName").html(selname); var dataString = 'selname='+ selname; $.ajax({ type: "POST", url: "getdatabyname.php", data: dataString, cache: false, success: function(data) { $("#Schedule").html(data); } }); } }); CopyPHP<?phprequire_once ('../include/global.php'); if($_POST['selname']) { $selname = $_POST['selname']; $sql="SELECT * FROM clinic.appoint WHERE name='$selname'"; $result = mysqli_query($con, $sql) ordie($sql."<br/><br/>".mysql_error()); while($rows=mysqli_fetch_array($result)){ ?><tr><tdscope="row"><?phpecho$rows['time'] ?></td><tdscope="row"><?phpecho$rows['name'] ?></td><tdscope="row"><?phpecho$rows['date'] ?></td><tdscope="row"><formaction='/clinic form/appoint/delete.php'=<?phpecho$rows['id']; ?>' method="post"><inputtype="hidden"name="id"value="<?phpecho$rows['id']; ?>"><inputtype="submit"name="submit1"value="Done"></form></td></tr><?php } } ?>Copy(OP reached me via email and explained what he is trying to do) Now, you are fetching result by 2 different <select> element using Ajax and trying to show the result based on <select> element and in both Ajax calls success: function you are targeting 2 different id's to show the data for each <select> Ajax call e.g//For Date Result $("#Schedule").html(data); //For Name Result $("#Schedule2").html(data); CopyI would suggest to use the same id selector in both Ajax calls success: function to show the data$("#Schedule").html(data); CopyBy doing so, when you switch between select element, to show the data, it will replace the first fetched data.Last, I totally agree with @Jared Smith what he said about mixing PHP and JavaScript, it's really not good practice. Share Post a Comment for "Multiple Java Script In One Page Error" Top Question IE8 And Border Css Property On Select Menus I am getting a really strange behaviour when viewing a very… Twitter REST API: Possible To Hotlink Twitter Images? Why No Image Display In Firefox? I am trying to extract images from Twitter REST API and dis… Force Download For Blob Created With FileWriter In JavaScript HTML5 introduces the FileWriter class. With this class you … How Can One Make A Container's Child Divs Match The Width Of The Largest Child In IE7? This seems like it should be a duplicate - I've found m… Show Hide Div In One Area I have been looking all day to try and find something that … Why My Website Display Only One Image On IPad? I have problems with my website. There is displayed only on… Html Formatted Text In An Email In Java try{ String msg='Happy BirthDay Dear, '+na… Collapsible Panel In Html/css I'm putting together a website. I need help creating th… Force A Div To Show Up And Overlay Whatever Is In Fullscreen I have a Chrome extension that inserts a menu into the page… What Is The Correct Way For Redirecting From The Domain Name Itself To A Page In A Directory? I want anyone browsing for 'MyDomain.com' to see wh… December 2024 (1) November 2024 (40) October 2024 (59) September 2024 (20) August 2024 (362) July 2024 (338) June 2024 (685) May 2024 (1285) April 2024 (776) March 2024 (1534) February 2024 (1715) January 2024 (1344) December 2023 (1408) November 2023 (439) October 2023 (703) September 2023 (310) August 2023 (330) July 2023 (275) June 2023 (344) May 2023 (212) April 2023 (138) March 2023 (136) February 2023 (170) January 2023 (270) December 2022 (124) November 2022 (231) October 2022 (176) September 2022 (163) August 2022 (290) July 2022 (93) Menu Halaman Statis Beranda © 2022 - Html5 Tutorial